SENIOR ELEMENTARY TEACHER SET PAST PAPERS AND SYLLABUS
چار آپشن میں سے کسی ایک پر کلک کرنے سے جواب سرخ ہو جائے گا۔
کون سا کوانٹم نمبر سیٹ درست نہیں ہے؟
- n = 3, l = 3, m = 2, s = 1/2
- n = 4, l = 2, m = 0, s = -1/2
- n = 3, l = 2, m = 1, s = +1/2
- n = 2, l = 1, m = 0, s = -1/2
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
- Quantum numbers must follow fixed rules.
- For a given principal quantum number n, azimuthal quantum number l = 0 to (n−1).
- If n = 3, possible l values are 0, 1, 2 only.
- So l = 3 is not allowed for n = 3.
- Therefore that set is invalid.
Last verified on 20-05-2026
- 10
- 11
- 12
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
For l=2, it represents the d-subshell.
A d-subshell has 5 orbitals, and each orbital can hold 2 electrons.
So total electrons = 5 × 2 = 10.
Last verified on 20-05-2026
- O₂
- H₂
- CO₂
- N₂
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
- Effusion is the escape of gas molecules through a tiny hole.
- According to Graham’s law, rate of effusion ∝ 1/√molar mass.
- Lighter gases effuse faster than heavier gases.
- Among given options, hydrogen has the lowest molar mass (H₂ = 2 g/mol).
- Therefore, it moves and escapes the fastest.
Last verified on 19-05-2026
مائع–بخار توازن میں بخارات کے دباؤ میں اضافہ کس سے ہوگا؟
- Increase pressure
- Decrease temperature
- Increase temperature
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
- Vapour pressure depends on the tendency of liquid molecules to escape into vapour.
- When temperature increases, molecules gain kinetic energy.
- More molecules escape from liquid phase into vapour phase.
- This increases the vapour pressure at equilibrium.
- Pressure applied from outside does not increase vapour pressure directly.
Last verified on 20-05-2026
- Hydrogen bonding
- Ionic bonding
- Covalent bonding
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
- Boiling point depends on intermolecular forces.
- Stronger forces require more energy to separate molecules.
- Water (H₂O) forms strong hydrogen bonding between molecules.
- H₂S has only weak van der Waals (no effective hydrogen bonding).
- Therefore, water has a much higher boiling point.
Last verified on 20-05-2026
سپر کریٹیکل فلوئیڈ کے بارے میں کون سا بیان درست ہے؟
- It behaves only as a solid
- It has fixed shape and volume
- No boundary exists between gas and liquid phases
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
- A supercritical fluid forms above critical temperature and pressure.
- In this state, substance shows properties of both liquid and gas.
- It can diffuse like a gas and dissolve substances like a liquid.
- The liquid and gas phases become indistinguishable.
- Therefore, no clear boundary exists between them.
Last verified on 19-05-2026
- CH₄
- NH₃
- Diborane (B₂H₆)
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
- A 3-center 2-electron (3c–2e) bond involves three atoms sharing two electrons.
- This type of bonding occurs in electron-deficient compounds.
- Diborane (B₂H₆) is a famous example of such bonding.
- It contains two bridging hydrogen atoms between boron atoms.
- These bridges form banana-shaped 3c–2e bonds.
Last verified on 19-05-2026
آکسیجن کی آئنائزیشن انرجی نائٹروجن سے کم کیوں ہوتی ہے؟
- Oxygen has larger atomic size
- Oxygen has paired electrons causing repulsion in p subshell
- Nitrogen has higher nuclear charge
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
- Ionization energy is energy required to remove an electron from an atom.
- Nitrogen has configuration: 1s² 2s² 2p³ (half-filled, stable).
- Oxygen has configuration: 1s² 2s² 2p⁴.
- In oxygen, one p orbital has paired electrons, causing repulsion.
- This repulsion makes electron removal easier in oxygen than nitrogen.
Last verified on 19-05-2026
- 200 K
- 300 K
- 400 K
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
For spontaneity, use Gibbs free energy:
ΔG = ΔH - TΔS
Reaction becomes non-spontaneous when ΔG > 0.
At the cutoff point ΔG = 0, so:
0 = ΔH - TΔS
T = ΔH / ΔS
Plug in the values. Convert ΔH to J/mol to match units:
ΔH = −40 kJ mol⁻¹ = −40000 J mol⁻¹
ΔS = −100 J mol⁻¹ K⁻¹
T = (−40000) / (−100) = 400 K
Last verified on 19-05-2026
- Molar concentration increases, specific conductivity decreases
- Molar concentration decreases, specific conductivity decreases
- Both increase
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
- Dilution means adding more solvent (water) to a solution.
- Molar concentration depends on amount of solute per volume.
- When volume increases, molarity decreases.
- Specific conductivity depends on number of ions per unit volume.
- So both concentration and conductivity decrease on dilution.
Last verified on 19-05-2026