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Consider the given reaction: N₂ + 3H₂ → 2NH₃ If 56 g of N₂ reacts with 12 g of H₂ and produces 51 g of NH₃, what is the theoretical yield (TY) of NH₃ and the percentage yield (PY) of the reaction? (Molar mass of N₂ = 28 g/mol, H₂ = 2 g/mol and NH₃ = 17 g/mol)
  1. TY = 34 g and PY = 33%
  2. TY = 68 g and PY = 75%
  3. TY = 34 g and PY = 75%
  4. None of these
Explanation

Moles: N₂ = 56/28 = 2 mol, H₂ = 12/2 = 6 mol → stoichiometric (2 mol N₂ needs 6 mol H₂).

Theoretical NH₃ = 2×2 = 4 mol → 4×17 = 68 g; % yield = (51/68)×100 = 75%.

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