Explanation

- Start time: 08:50

- Registration: 10 minutes → 08:50 + 10 min = 09:00

- 3 lessons × 55 minutes = 165 minutes → 09:00 + 165 min = 11:45

- Break: 15 minutes → 11:45 + 15 min = 12:00

- Lunch: 1 hour → 12:00 + 1 hour = 13:00

Explanation

Work = Number of workers × Time

Let’s find the total work in worker-hours:

- 8 workers × 36 hours = 288 worker-hours

Now, to finish the work in 8 hours, let’s find how many total workers are needed:

- 288 ÷ 8 = 36 workers

We already have 8 workers, so additional workers needed:

- 36 − 8 = 28

Explanation

We are given a letter pair sequence: AD, DF, EH, ?

First letters:

- A → D (+3)

- D → E (+1)

- E → G (+2)

So the pattern in first letters is: +3, +1, +2

Second letters:

- D → F (+2)

- F → H (+2)

- H → J (+2)

So the pattern in the second letters is consistently +2

Therefore, the missing pair is:

GJ

Explanation

Let the first part be x, lent at 10% for 8 years.  

So, interest = (x × 10 × 8)/100 = 0.8x

Let the second part be (4200 − x), lent at 7% for 5 years.  

So, interest = [(4200 − x) × 7 × 5]/100 = (35/100)(4200 − x) = 0.35(4200 − x)

Since both interests are equal:

0.8x = 0.35(4200 − x)

Solve:

0.8x = 1470 − 0.35x  

0.8x + 0.35x = 1470  

1.15x = 1470  

x = 1278.26

So, second part = 4200 − 1278.26 = Rs. 2,921.74 ≈ Rs. 2,921

Explanation

Each group  is made of 3 consecutive letters in reverse alphabetical order:

- HGF → H, G, F  

- WVU → W, V, U  

- EDC → E, D, C  

Following this reverse-letter pattern:

- After EDC, the next reverse set would be:  

  C, B, A → CAB

Explanation

EFG, LMN, ___, STU

Each group has 3 consecutive letters.

EFG → E, F, G (5th, 6th, 7th letters)  

LMN → L, M, N (12th, 13th, 14th letters)  

STU → S, T, U (19th, 20th, 21st letters)

The missing group must be the letters between N (14th) and S (19th), which are O, P, Q, R.

We need a group of three consecutive letters before S, T, U, after L, M, N.

So after LMN (12,13,14), the next triple is:  

O, P, Q (15,16,17)

Explanation

R Q Q R R Q R Q R R → ?

Using the same mapping (Q=4, R=5), replace each letter with corresponding digit:

R Q Q R R Q R Q R R  

5 4 4 5 5 4 5 4 5 5

So the answer is: 5445545455

Explanation

Given the cryptarithm:

C + CA = ATT

Where:

- C is a single digit number.

- CA is a two-digit number with C in the tens place and A in the units place.

- ATT is a three-digit number with A in hundreds, and T in tens and units.

Rewrite the equation numerically:

C + (10 × C + A) = 100 × A + 10 × T + T

Simplify:

C + 10C + A = 100A + 11T  

11C + A = 100A + 11T  

11C + A - 100A = 11T  

11C - 99A = 11T  

Divide both sides by 11:  

C - 9A = T

Since C, A, T are digits 0-9:

- C - 9A = T  

- T must be a digit 0-9  

- So, C - 9A ≥ 0 and ≤ 9

Try possible values of A from 1 to 9 (A cannot be zero, since it is the hundred's digit in ATT):

Check A = 1:  

C - 9*1 = T ⇒ C - 9 = T  

Since T ≥ 0, C ≥ 9. So C=9, then T=0.

Check if this works numerically:

Left side:  

C + CA = 9 + 91 = 100

Right side:  

ATT = 1 0 0 = 100

Matches!

So the possible value of C is 9.

Explanation

Given series: 459, 440, ?, 402, 383

Difference between terms:  

459 - 440 = 19  

402 - 383 = 19  

Assuming constant difference of 19:  

? = 440 - 19 = 421

Explanation

1. Number of Parallelograms in a 2×3 grid

Formula: Total = (m(m+1)/2) × (n(n+1)/2)  

= (2×3/2) × (3×4/2) = 3 × 6 = 18

Answer: 18 (not in options, closest is 16)