COMBINED COMPETITIVE EXAMINATION PAPER 2025
CCE 5 years Past Papers Clickhere
چار آپشن میں سے کسی ایک پر کلک کرنے سے جواب سرخ ہو جائے گا۔
- 250
- 260
- 270
- None of these
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Explanation
c² = 150² + 200² = 62500.
c = 250 cm.
- 25
- 24
- 23
- None of these
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Explanation
75% had at least one lunch → 25% had none.
25% × 96 = 24 people ate neither.
- -12
- -19
- 18
- None of these
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Explanation
Simplify each term: (2/3 × 45) = 30, 3⅘ = 3.8, 20.
Total = -19.
- 624613
- 624624
- 624635
- 624646
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Explanation
A number divisible by 7, 11 and 13:
= LCM of 7, 11 and 13
= 1001
A number which is multiple of 1001 is of the form:
Xyz xyz …….. (digits repeating)
Answer: 624624
- 3070
- 3069
- 3072
- None of these
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Explanation
Common ratio r = 2.
Sum of 10 terms = 3 × (2¹⁰ - 1) = 3069
- Composite numbers
- Prime numbers
- Co-prime numbers
- None of these
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Explanation
Each pair (2,5), (4,7), (17,6) has no common factor other than 1.
Hence, they are co-prime (relatively prime) numbers.
- 47/66
- 66/91
- 75/91
- None of these
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Explanation
Total ways = (12 2) = 66; same color ways = 10 + 6 + 3 = 19
Different color ways = 66 - 19 = 47; so probability = 47/66.
- @#!^
- #@^*
- !#*^
- None of these
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Explanation
From DRAIN → ^!#*@, we get the mapping: D→^, R→!, A→#, I→*, N→@.
Encode NARD as N(@) A(#) R(!) D(^) → @#!^.
- 263
- 625
- 103
- None of these
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Explanation
For 123 → 13², the first and last digits 1 and 3 form 13, then squared gives 169.
Apply same rule to 235 → first and last digits 2 and 5 form 25, squared gives 625.
- 2 ways
- 5 ways
- 24 ways
- 120 ways
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Explanation
The word CHORD has 5 distinct letters: C-H-O-R-D.
When taking all the letters together, the number of ways to arrange them is equal to the number of permutations of 5 items, which is calculated as:
5! = 5 × 4 × 3 × 2 × 1 = 120