A box contains 5 red balls, 4 blue balls and 3 green balls. Two balls are drawn at random without replacement. What is the probability that both balls are of different colors?
- 47/66
- 66/91
- 75/91
- None of these
Explanation
Total ways = (12 2) = 66; same color ways = 10 + 6 + 3 = 19
Different color ways = 66 - 19 = 47; so probability = 47/66.
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