ALL FPSC PAST PAPERS MCQS OF BASIC ARITHMETIC 1998 TO 2019
چار آپشن میں سے کسی ایک پر کلک کرنے سے جواب سرخ ہو جائے گا۔
- 13
- 14
- 15
- None of these
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Explanation
Let's calculate the total man-hours required to complete the work:
39 persons * 5 hours/day * 12 days = 2340 man-hours
If 30 persons work 6 hours a day:
Let x be the number of days they need to complete the work:
30 persons * 6 hours/day * x days = 2340 man-hours
180x = 2340
x = 13
- 29
- 37
- 42
- 54
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Explanation
After 10 days: 150 men had food for 35 days.
Suppose 125 men had food for x days.
Now, Less men, More days (Indirect Proportion)
125 : 150 :: 35 : x 125 x x = 150 x 35
x = 150 x 35
125
x = 42.
- 12
- 13
- 14
- None of these
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Explanation
Let's calculate the total pump-hours required to empty the tank:
3 pumps * 8 hours/day * 2 days = 48 pump-hours
If 4 pumps need to empty the tank in 1 day:
Let x be the number of hours they need to work:
4 pumps * x hours/day * 1 day = 48 pump-hours
4x = 48
x = 12
- 10/21
- 4/7
- 2/7
- None of these
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Explanation
Probability = 5C2/7C2 = 10/21
Total number of balls = 2 + 3 + 2 = 7
∴ Number of ways of drawing 2 balls out of 7 = 7C2 = (7 × 6) / (2 × 1) = 42/2 = 21
Number of balls other than blue = 5
∴ Number of ways of drawing 2 balls out of 5 = 5C2 = (5 × 4) / (2 × 1) = 20/2 = 10
∴ Required Probability = 10/21
- 53,900
- 54,080
- 54,000
- None of these
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Explanation
Let's calculate the population after 2 years:
Year 1:
Population = 50,000 + (4% of 50,000)
= 50,000 + 0.04 * 50,000
= 50,000 + 2,000
= 52,000
Year 2:
Population = 52,000 + (4% of 52,000)
= 52,000 + 0.04 * 52,000
= 52,000 + 2,080
= 54,080
The population after 2 years will be 54,080.
- 10 m
- 17.5 m
- 12.5 m
- 21.25 m
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Explanation
Let the height of the building be x meters.
Less lengthy shadow, Less in the height (Direct Proportion)
∴ 40.25 : 28.75 :: 17.5 : x ⇔ 40.25 × x = 28.75 × 17.5
x = 28.75 × 17.5/ 40.25 ⇒ x = 12.5
- 700
- 800
- 600
- None of these
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Explanation
25% of x = 150
0.25x = 150
x = 150 / 0.25
x = 600
- 6
- 8
- 10
- None of these
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Explanation
Let's solve:
3 men = 6 boys (given)
1 man = 2 boys
Work done by 3 men or 6 boys in 20 days:
Let's calculate work done by 1 boy in 1 day:
6 boys * 20 days = 120 boy-days
Now, 6 men and 8 boys:
6 men = 6 * 2 = 12 boys
Total = 12 boys + 8 boys = 20 boys
Time taken = 120 boy-days / 20 boys = 6 days
- 14
- 8
- 12
- None of these
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Explanation
15 men complete the work in 8 days
Total work = 15 men * 8 days = 120 man-days
Now, to complete the work in 10 days:
120 man-days / 10 days = 12 men
- 370 men
- 360 men
- 380 men
- 410 men
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Explanation
1/240 * n * 4 = 6 becomes:
1/240 * 360 * 4 = 6
we simplify to get:
6 = 6 confirming that our calculation of the number of people required is good.
the answer is that it would require 360 men to fill 6 holes in 4 months.