If (a + bi)(a - bi) = 89 and a+ b = 10 then a² + b² equals?
- 89
- 90
- 91
- None of these
Explanation
If you multiply (a + bi) and (a - bi), you get:
(a + bi)(a - bi) = a_a - a_bi + bi_a - bi_bi
= a^2 - abi + abi - b^2_i^2
The middle terms cancel out. And i^2 = -1, so -b^2_i^2 = -b^2*(-1) = b^2.
That leaves a^2 + b^2.
You are told (a + bi)(a - bi) = 89, so a^2 + b^2 = 89.
Last verified on 25-05-2026
Related MCQs
- Infinite value
- Finite value
- Can't be found
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- Ā × B̄ = 0̄
- Ā + B̄ = 0̄
- Ā - B̄ = 0̄
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- F(ln a)
- f(a)
- f(e^x)
- f(1/a)
اس سوال کو وضاحت کے ساتھ پڑھیں
- [1 2, 2 1, 1 3] [x1, x2, x3] = [9 7]
- [3 1, 2 1, 1 2] [x1, x2, x3] = [9 7]
- [1 2, 2 1, 1 3] [x1, x2, x3] = [7 9]
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- d²x/dt² = - m²x
- d²x/dt² = + m²x
- d²x/dt² = ± m²x
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Leave a Reply
Your email address will not be published. Required fields are marked *