If y ∝ 1/(x²) and y = 18 when x = 3 find y when x = 6?
- 4
- 5
- 6
- None of these
Explanation
If y ∝ 1/(x²) and y = 18 when x = 3, then y = 4.5 when x = 6
Solution:
Since y is inversely proportional to x², we can write
y = k / x², where k is a constant.
When y = 18 and x = 3,
18 = k / 3²
18 = k / 9
k = 18 * 9 = 162
Now put k = 162 and x = 6 to find y,
y = 162 / 6²
y = 162 / 36
y = 4.5
So y = 4.5 when x = 6
Last verified on 24-05-2026
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