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Sticky Note
If x² - px + 56 has factors differing by 1, then p equals?
  1. 13
  2. 14
  3. 15
  4. None of these
Explanation

Let the factors be (x - a) and (x - (a+1)) because they differ by 1.

Multiply them:

(x - a)(x - a - 1) = x^2 - (2a + 1)x + a(a + 1)

Compare with x^2 - px + 56:

a(a + 1) = 56

p = 2a + 1

Solve a(a + 1) = 56

a^2 + a - 56 = 0

(a + 8)(a - 7) = 0

So a = 7 or a = -8

If a = 7, then p = 2_7 + 1 = 15

If a = -8, then p = 2_(-8) + 1 = -15


Last verified on 23-05-2026

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