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A is twice as good as workman as B and together they finish a piece of work i 18 days. In how may days will B alone finish the work?
  1. 27 days
  2. 54 days
  3. 56 days
  4. 68 days
Explanation

Given:  

- A is twice as good a workman as B  

→ A’s work rate = 2 parts, B’s = 1 part  

→ Combined rate = 3 parts  

- Together they finish the work in 18 days  

→ So total work = 3 × 18 = 54 units


Now, B alone does 1 part/day ⇒  

Time B alone will take = 54 / 1 = 54 days


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