A is twice as good as workman as B and together they finish a piece of work i 18 days. In how may days will B alone finish the work?
- 27 days
- 54 days
- 56 days
- 68 days
Explanation
Given:
- A is twice as good a workman as B
→ A’s work rate = 2 parts, B’s = 1 part
→ Combined rate = 3 parts
- Together they finish the work in 18 days
→ So total work = 3 × 18 = 54 units
Now, B alone does 1 part/day ⇒
Time B alone will take = 54 / 1 = 54 days
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