A father was twice the age of her daughter 4 years ago. The sum of their ages is 47. What is the daughter's age today?
- 14
- 15
- 16
- 17
Explanation
Let daughter's age = x
Then father’s age = 47 - x
4 years ago:
Father's age = 47 - x - 4 = 43 - x
Daughter's age = x - 4
Given: Father was twice the daughter's age 4 years ago
43 - x = 2(x - 4)
43 - x = 2x - 8
43 + 8 = 3x ⇒ 51 = 3x ⇒ x = 17
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