What is the value of (i^25 - (1/i)^32)^2?
- 2i
- -2i
- 1
- -1
Explanation
i^25 = i^(24+1) = i^1 = i (since i^4 = 1)
(1/i)^32 = (i^-1)^32 = i^(-32) = i^0 = 1 (since i^4 = 1)
So, (i^25 - (1/i)^32)^2
= (i - 1)^2
= i^2 - 2i + 1
= -1 - 2i + 1
= -2i
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