Explanation

B2CD,BC3D,BCD4, B5CD, BC6D

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B2CD

BC3D

BCD4

B5CD

BC6D

BCD7

Explanation

• What will be the 147th term of the following pattern? 25,45,65,85,2945
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• We will use the following formula to find out the 147th term.
  an = a1 + (n - 1)d
  
• 
  

Explanation

look at the series 8,22,8,28,6,34
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8

22+6=28

8

28+6=34

Explanation

Look at the series 1.5, 2.3, 3.1, and 3.9,   4.7

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1.5 +0.8=2.3

2.3+0.8=3.1

3.1+0.8=3.9

3.9+0.8=4.7

Explanation

ZA5, Y4B, XC6, W3D,VE7.

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First of all, read backward A B C. Then read A  B C from the start

Z,Y,X,W,V……..

A,B,C,D,E,……….

5,4,6,3,7,………

Explanation

Look at the series and complete it: 72,76,73,77,7, 78,.75

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72+4=76

76-3=73

73+4=77

77-3=74

74+4=78

78-3=75

Explanation

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Explanation

214 - 17 = 197

197 - 18 = 179

179 - 19 = 160

160 - 20 = 140

Explanation

Let, a and b two given numbers.

Let,

$A_1,A_2,A_3.............A_n$ be Arithmetic means between a and b.

$a,A_1,A_2,A_3.............A_n,b$ are in A.P.

$a+A_1+A_2+A_3+......A_n+b=\left(\frac{n+2}{2}\right)\left(a+b\right)$      (first term is =a, last term=b, number of term=n+2)

  $A_1,A_2,A_3.............A_n=\frac{\left(n+2\right)\left(a+b\right)}{2}-(a+b)$

 $=\left(a+b\right)\left[\frac{n+2}{2}-1\right]$

 $=\left(a+b\right)\left[\frac{n+2-2}{2}\right]$

 $=n\left(\frac{a+b}{2}\right)$

$SH14-8-2023$

Explanation

10+1=11 11-2=9 9+3=12 12-4=8 8+5=13 13-6=7 7+7=14 14-8=6 6+9=15.