Explanation

The rate at which Masons build walls is what we need to understand with this problem.

15*X = 20

15*X/20 = 1 Wall

Therefore, a fifteenth of a wall can be built by one mason in 20 days.

Each day, a mason can build 1/(15*20) or 1/300th of an entire wall.

Therefore, it would take one mason 300 days to build a wall on their own.

It would take 15 masons 20 days (300/20) to build a wall.

And we can estimate the 12 day solution with the following formula:

300/12 = 25

It would take 25 masons 12 days .

Explanation

You get that after subtracting 60 from a number. So before subtracting, it should have been 60 + 60 = 120. 120 in the mind.

Now this number is 60% of some other number. Now now, don't pick up your calculator. 60% of something is 120. So what is 10% of it? 120/6 = 20. And hundred percent of it? yeah, 20*10 = 200.

Explanation

2+4+6

=12/3=4

Explanation

Three men (Amir, adil and fahad) and three women (Rani, anne and kiran) are sspending a few months ar a hillside. They are to stay in a row of nine cottages, each one living in his or her own cottage. There are no others staying in the same row of houses.

I) Anne, Amir, and Fahad do now want to stay in any cottage, which is at the end of the row.

II) Riani and Anna are unwilling to stay beside any occupied cottage.

III) Krian is next to adil and fahad

IV) Between anne ade fahad cottage there is just one vacant house.

V) None of the girls occupy adjacent cottages.

VI) The house occputied by amir is next to an end cattage.

Question:

which of the above statements can be said to have been derived from two other statements?

A) Statement I

B) Statement V

C) Statement II

D) Statement III

E) Statement VI

Explanation

Prime numbers are numbers that have only 2 factors: 1 and themselves.

Explanation

  28032/384=73

Explanation

Net eastward displacement =1+2=3 miles

Net northward displacement  =−5+9=4 miles
Net displacement  d=3i^+4j^​
∣∣∣∣​d∣∣∣∣​=32+42​=5 miles

Net eastward displacement =1+2=3 miles
Net northward displacement  =−5+9=4 miles
Net displacement  d=3i^+4j^​
∣∣∣∣​d∣∣∣∣​=32+42​=5 miles