UAF ENTRY TEST PAST PAPER 23-07-2017
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چار آپشن میں سے کسی ایک پر کلک کرنے سے جواب سرخ ہو جائے گا۔
پتی کے ہر میسوفیل سیل میں _____ کے بارے میں کلوروپلاسٹ ہوتے ہیں؟
20 - 100
10 - 20
120 - 150
None of these
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Explanation
Each mesophyll cell in a leaf typically contains about 20 to 100 chloroplasts, depending on the plant species .
These chloroplasts are the site of photosynthesis, capturing sunlight to produce food.
صحرا ماحولیاتی نظام بکھر اور میانوالی کے ____ کو کہا جاتا ہے؟
That
Thal
Rohi
None of these
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Explanation
The desert ecosystem of Bhakkar and Mianwali districts in Punjab, Pakistan is known as the Thal Desert .
It is a sandy, arid region located between the Indus and Jhelum rivers.
پھیپھڑوں کے الیوولی کو توڑنے کو ______ کہا جاتا ہے؟
Asthma
Tuberculosis
Emphysema
Lungs cancer
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Explanation
The breakdown of alveoli in the lungs is called Emphysema .
Emphysema is a lung condition where the s mall air sacs (alveoli) are damaged, causing them to break down and merge into larger spaces, reducing the surface area available for gas exchange.
میٹھی مٹر کا کنبہ _____ ہے؟
Fabaceae
Solanaceae
Rosaceae
Poaceae
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Explanation
Sweet peas are annual climbing plants with fragrant, butterfly-shaped flowers.
They are part of the genus Lathyrus within the Fabaceae family.
The name Lathyrus is derived from the Greek word for "pea," and odoratus means "scented".
They are cultivated for their beautiful and fragrant flowers.
پروٹوسٹومس میں ، بلاسٹ پور _____ تشکیل دیتا ہے؟
Mouth
Brain
Anus
Excretory pore
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Explanation
A protostome is an animal where the first opening that forms during embryonic development (the blastopore) becomes the mouth.
While the second opening develops into the anus.
10 g
6 g
2 g
4 g
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Explanation
To prepare 250 cm³ (or 250 mL) of a 1 M NaOH solution, you need 10 grams of NaOH.
This is because the molar mass of NaOH is 40 g/mol, and a 1 M solution contains 1 mole of solute per liter of solution.
Therefore, 250 mL (0.25 L) of a 1 M solution would require 0.25 moles of NaOH, which translates to 10 grams (0.25 moles * 40 g/mol).
چھوٹے سوراخ سے گیس کے انووں سے فرار _____ کہا جاتا ہے؟
Diffusion
Effusion
Osmosis
None of these
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Explanation
Effusion is the process by which gas particles pass through a tiny hole without collisions between particles. It is described by Graham’s Law , which relates effusion rate to molar mass.
وین ڈیر والز کی تعمیل کرنے والی ایک حقیقی گیس مثالی گیس سے ملتی جلتی ہوگی اگر ______؟
Both A and B small
Both A and B larger
A small and B larger
None of these
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Explanation
In Van der Waals equation , ‘ a ’ accounts for intermolecular forces and ‘ b ’ for volume of gas molecules. A small ‘a’ (weak attraction) and large ‘b’ (small molecular size) make a real gas behave more like an ideal gas.
0.50
0.25
1.50
None of these
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Explanation
Step 1: Calculate moles of oxygen 8.0 g O / 16 g/mol = 0.5 mol O
Step 2: Calculate moles of CO₂
Since CO₂ has 2 O atoms, moles of CO₂ = 0.5 mol O / 2 = 0.25 mol CO₂
Zero
+1
+2
None of these
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Explanation
Let oxidation number of O = x x + 2(-1) = 0
x - 2 = 0
x = +2
The oxidation number of oxygen in OF₂ is +2 .