During a Hajj field movement operation, a vehicle travels 36 km at 45 km/h, then 24 km at 30 km/h, waits 12 minutes, and returns 60 km at 40 km/h. Total elapsed time?
- 3 hours 30 minutes, treating the speed change as extra delay.
- 3 hours 18 minutes, being 48 + 48 12 minutes plus 1 hour 30 minutes.
- 2 hours 48 minutes, using an overall average speed.
- None of these
Explanation
Step 1: Find time for each part
Time = Distance / Speed
Part 1: 36 km at 45 km/h = 36 / 45 = 0.8 hours = 48 minutes
Part 2: 24 km at 30 km/h = 24 / 30 = 0.8 hours = 48 minutes
Part 3: Wait = 12 minutes
Part 4: Return 60 km at 40 km/h = 60 / 40 = 1.5 hours = 90 minutes = 1 hour 30 minutes
Step 2: Add all times
48 minutes + 48 minutes + 12 minutes + 90 minutes = 198 minutes
198 minutes = 3 hours 18 minutes
Answer: 3 hours 18 minutes, being 48 + 48 + 12 minutes plus 1 hour 30 minutes.
Last verified on 11-09-2026
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- 3 hours 30 minutes, treating the speed change as extra delay.
- 3 hours 18 minutes, being 48 + 48 12 minutes plus 1 hour 30 minutes.
- 2 hours 48 minutes, using an overall average speed.
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