A 3-digit number is reversed, and the new number is 297 greater than the original. The sum of the first and third digits is 7. What is the product of the first and third digits?
- 10
- 12
- 14
- None of these
Explanation
Let the 3-digit number be abc = 100a + 10b + c
Reversed = cba = 100c + 10b + a
Given: reversed - original = 297
(100c + 10b + a) - (100a + 10b + c) = 297
99c - 99a = 297 → 99(c - a) = 297 → c - a = 3
Also given: a + c = 7
Solve:
a + c = 7
c - a = 3
Add both: 2c = 10 → c = 5
Then a = 7 - 5 = 2
Product of first and third digits = a × c = 2 × 5 = 10.
Last verified on 23-06-2026
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