The sum of the ages of father and son is 72 years. Six years ago, the father's age was twice the son's age. What was the son's age six years ago?
- 18 years
- 20 years
- 22 years
- None of these
Explanation
Father = F, Son = S
Given:
F + S = 72 …(1)
Six years ago:
F − 6 = 2(S − 6) …(2)
Solve (2):
F − 6 = 2S − 12
F = 2S − 6 …(3)
Put in (1):
(2S − 6) + S = 72
3S − 6 = 72
3S = 78
S = 26
Son’s present age = 26
Son’s age 6 years ago = 26 − 6 = 20 years
Last verified on 10-05-2026
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