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X:y=3:4 , y:z= 5:8 then find 2y/ 3x-y+2z?
  1. 45/49
  2. 40/89
  3. 50/89
  4. 36/89
Explanation

Given:


X : Y = 3 : 4 quad text{and} quad Y : Z = 5 : 8

Step 1: Make Y common

  • From , let, Y = 4k

  • From
    Y:Z = 5:8    , let
    Y = 5m    ,

Step 2: Equate Y


4k = 5m implies k = frac{5}{4} m

Then:


X = 3k = 3 cdot frac{5}{4} m = frac{15}{4} m
Y = 4k = 5m Z = 8m

Step 3: Compute the expression


frac{2Y}{3X - Y + 2Z} = frac{2 cdot 5m}{3 cdot frac{15}{4} m - 5m + 2 cdot 8 m}3X−Y+2Z​=2⋅5m/ 3⋅15​/4m−5m+2⋅8m​

Numerator:

Denominator:


frac{2Y}{3X - Y + 2Z} = frac{10 m}{frac{89}{4} m} = frac{10 cdot 4}{89} = frac{40}{89}3X−Y+2Z​=10m​/89/4=10⋅4/89​=40/89​

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