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If a² - b² = 9 and (a - b)² = 3, then what is the value of ab?
  1. 2
  2. 3
  3. 4
  4. 6
Explanation

a² − b² = 9  

But we can also write:


a² − b² = (a + b)(a − b) = 9  

And  

(a − b)² = 3 → so (a − b) = √3 or −√3


Let’s assume:  

a − b = √3


Then:  

From (a + b)(a − b) = 9  

⇒ (a + b)(√3) = 9  

⇒ a + b = 9 / √3 = 3√3


Now, we have:  

a + b = 3√3  

a − b = √3


Now solve the system:


Adding:  

2a = 4√3 → a = 2√3  

Subtracting:  

2b = 2√3 → b = √3


Now, ab = a × b = 2√3 × √3 = 2 × 3 = 6


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