A number of solutions of equation √y + √y+3=1 is?
- 0
- 2
- 1
- None of these
Explanation
Number of Solutions
Given: √y+ √y + 3 = 1
Let's solve it:
√y + 3 = 1 - √y
Squaring both sides:
y + 3 = 1 - 2 √y + y
2 = -2 √y
√y = -1
Since √y = 0 for all y = 0, there's no real solution for y.
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