a, A₁, A₂, A₃, ..., Aₙ, b If it’s an arithmetic progression, then:
- Aₙ = a + n(b − a)/n
- Aₙ = a + n(b − a)/(n + 1)
- Aₙ = a − n(b + a)/(n + 1)
- Aₙ = b + n(a − b)/n
Explanation
Aₙ = a + n × d, where d = common difference
Here, A₁ = a + d, A₂ = a + 2d, ..., b = a + (n+1)d
So,
Aₙ = a + n × [(b − a)/(n + 1)]
Related MCQs
Leave a Reply
Your email address will not be published. Required fields are marked *
