tan θ + cot θ = _____?
- sec θ cos θ
- sin θ cosec θ
- sec θ cosec θ
- None of these
Explanation
tan θ = sin θ/cos θ and cot θ = cos θ/sin θ
tan θ + cot θ = sin θ/cos θ + cot θ = cos θ/sin θ
= sin^2 θ + cos^2 θ/sin θ cos θ
= 1/sin θ cos θ (since sin² θ + cos² θ = 1)
Now, 1/sin θ cos θ = 1/sin θ × 1/cos θ = cosec θ × sec θ = sec θ cosec θ
The answer is sec θ cosec θ.
Related MCQs
- 25
- 30
- 35
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 10x = - 3
- 2x = - 27
- 2x = 27
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 1, 4, -21
- 1, 4, 21
- -1, 4, -21
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 2/x + 12/(x +5)
- 3/x + 22/(x +5)
- 4/x + 16/(x +5)
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Leave a Reply
Your email address will not be published. Required fields are marked *