Which Is The Average Translational Kinetic Energy Of Molecules In A Gas At Temperature 27°C? - Testpoint

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Which is the average translational kinetic energy of molecules in a gas at temperature 27°C?

6.21 × 10⁻²³
6.21 × 10⁻²⁶
6.21 × 10⁻²¹
6.21 × 10⁻²⁹

Explanation

The average translational kinetic energy of a molecule in an ideal gas is given by the formula:

$E = 3/2 k T$

Where:

$k = 1.38 times 10^{-23} , text{J/K}$ (Boltzmann constant)
$T = 2 7^{\circ} C = 300 K$ (since 27°C + 273 = 300 K)

Now calculate:

$E = 3 \times 1.38 \times 1 0^^{- 23} \times 300$ $E = 3/2 \times 4.14 \times 1 0^^{- 21}$

$6.21 \times 1 0^^{- 21} J$

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