How many 5-digit multiples of 5 can be formed from the digits 2, 3, 5, 7, 9 when no digit is repeated?

Explanation

Step 1: Rule for divisibility by 5

A number is divisible by 5 if and only if it ends in 0 or 5.
But 0 is not among the given digits, so the last digit must be 5.

---

Step 2: Fix the last digit as 5

So, we fix 5 as the last digit.

Now we must choose the remaining 4 digits (from the remaining digits: 2, 3, 7, 9)
These will go in the first 4 places.

• Number of ways to arrange 4 digits out of 4 = 4! = 24

Related MCQs

Leave a Reply

Your email address will not be published. Required fields are marked *

Comment *

Name *

Email *

-- Select Reason -- Correction Suggestion

1 + 2 = ?

Post Comment