r ∝ 1/p³ and p = 9 when r = 2. Find p when r = 1/4?
- 18
- 17
- 15
- None of these
Explanation
r is inversely proportional to p³, so r = k/p³.
Given p = 9 and r = 2:
2 = k/729
k = 2 × 729 = 1458
Now, r = 1/4:
1/4 = 1458/p³
p³ = 1458 × 4 = 5832
p = 18
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