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Sticky Note
What is the value of the definite integral ∫₀¹ (2x + 1) dx?
  1. 1
  2. 1.5
  3. 2
  4. 2.5
Explanation

Step 1: Integrate the function

We integrate each term separately:


int (2x + 1), dx = int 2x, dx + int 1, dx = x^2 + x + C

Step 2: Apply the limits from 0 to 1

[x2+x]01=(12+1)−(02+0)=1+1=2left[ x^2 + x right]_0^1 = (1^2 + 1) - (0^2 + 0) = 1 + 1 = 2

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