If a sound note has intensity (I), equals to faintest audible sound (I₀), then will be it's sound level?
- 20 dB
- 10 dB
- 0 dB
- None of these
Explanation
The sound level β (in dB) is given by:
β = 10 log(I / I₀)
where I₀ is the threshold intensity (faintest audible sound). Given I = I₀:
β = 10 log(1) = 0 dB
Related MCQs
- -72
- -60
- -48
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- {1}
- {-1}
- {0}
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
