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Find the value of k if the roots of x² – 3x + k + 1 = 0 differ by unity?
  1. –3
  2. 1
  3. 2
  4. None of these
Explanation

Let's use the quadratic formula to find the roots:

x = (-b ± √(b² - 4ac)) / 2a

For the given equation x² - 3x + k + 1 = 0:

a = 1, b = -3, c = k + 1

The roots differ by unity, so:

√(b² - 4ac) = 1

(-3)² - 4(1)(k + 1) = 1

9 - 4k - 4 = 1

5 - 4k = 1

-4k = -4

k = 1

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