Nont:Quetsion contain 5 parts each parts contain 5 marks and total marks of the whole question is 20

(i) 1, 8, 4, 27, 9,?

This series alternates between cubes and squares:

$1 = 1^3$
$8 = 2^^{3}$
$4 = 2^^{2}$
$27 = 3^^{3}$
$9 = 3^^{2}$
Next: $4^^{3} = 64$

Missing number: 64

(ii) 3, 6, 8, 16, 18, ?

This series appears to follow a pattern:

First, $3 to 6$ (adding 3)
Then, $6 to 8$ (adding 2)
Next, $8 to 16$ (doubling)
Then, $16 \to 18$ (adding 2)
The next step likely doubles: $18 times 2 = 36$

Missing number: 36

(iii) 2, 8, 512, ?

This sequence involves raising the number to an increasing power of 3:

$Cube Series$
$2 x 2 x 2 = 8 (2^3=8)$
$8 x 8 x 8 = 512 (8^3 = 512)$
$512 x 512 x 512 = 134217728$

(iv) 81, 9, 64, 8, ?, 12

This pattern alternates between division and taking the square root:

$81 \div 9 = 9$
$64 div 8 = 8$
Next: $\sqrt{144} = 12$

$(v) 6, 11, 21, 36, 56, ?$

Addition of Multiples of 5

6+5 =11

11 + 10 = 21

21 + 15 = 36

36 + 20 = 56

56 + 25 = 81

Related MCQs

Find the missing number in the series below (i) 1, 8, 4, 27, 9, ? (ii) 3,6,8,16,18,? (iii) 2, 8, 512, ? (iv) 81 ,9,64 ,8,?,12 (v) 6, 11, 21, 36, 56, ?

Explanation

Nont:Quetsion contain 5 parts each parts contain 5 marks and total marks of the whole question is 20

(i) 1, 8, 4, 27, 9,?

(ii) 3, 6, 8, 16, 18, ?

(iii) 2, 8, 512, ?

(iv) 81, 9, 64, 8, ?, 12

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Find the missing number in the series below (i) 1, 8, 4, 27, 9, ? (ii) 3,6,8,16,18,? (iii) 2, 8, 512, ? (iv) 81 ,9,64 ,8,?,12 (v) 6, 11, 21, 36, 56, ?

Explanation

Nont:Quetsion contain 5 parts each parts contain 5 marks and total marks of the whole question is 20

(i) 1, 8, 4, 27, 9,?

(ii) 3, 6, 8, 16, 18, ?

(iii) 2, 8, 512, ?

(iv) 81, 9, 64, 8, ?, 12

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Latest Past Papers

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