Zaid is six times as old his daughter Zoya. How old was Zaid when Zoya was born if the sum of their ages will be 49 In 7 years?

Explanation

1. Current Ages:

   • Let Zoya’s current age be $x$
   • Then, Zaid’s current age is $6x$ (since he is six times as old as Zoya).

2. The sum of Ages in 7 Years:

   • In 7 years, Zoya's age will be $x + 7$ and Zaid's age will be $6x + 7$.
   • The sum of their ages in 7 years will be $(x+7)+(6x+7)=49$.

Step 1: Formulate the Equation

x+7+6x+7=49
$$7x+14=49$$

Step 2: Solve for $x$

Subtract 14 from both sides:

$$7x=35$$

Now divide by 7:

$$x=5$$

So, Zoya’s current age is $5$ years and Zaid’s current age is:

$$6x=6\times 5=30$$

Step 3: Determine Zaid’s Age When Zoya Was Born

When Zoya was born, Zaid would have been:

$$30-5=25$$

Related MCQs

Leave a Reply

Your email address will not be published. Required fields are marked *

Comment *

Name *

Email *

-- Select Reason -- Correction Suggestion

1 + 2 = ?

Post Comment