A container contains a mixture of milk and water in a ratio of 4:1. When 10 liters of the mixture are taken out and 10 liters of water are poured into the container and ratio becomes 2: 3. How many liters of milk were contained originally in the container?
- 16 litres
- 14 litres
- 12 litres
- None of these
Explanation
Initial ratio milk : water = 4 : 1
Let initial milk = 4x
Let initial water = x
Total = 5x
10 liters of mixture taken out.
In the mixture, milk = 4/5 and water = 1/5
Milk taken out = 10 × 4/5 = 8 liters
Water taken out = 10 × 1/5 = 2 liters
Remaining:
Milk = 4x - 8
Water = x - 2
Now 10 liters of water is added.
New Water = x - 2 + 10 = x + 8
New Milk = 4x - 8
New ratio milk : water = 2 : 3
So,
(4x - 8) / (x + 8) = 2 / 3
Cross multiply:
3(4x - 8) = 2(x + 8)
12x - 24 = 2x + 16
12x - 2x = 16 + 24
10x = 40
x = 4
Original milk = 4x = 4 × 4 = 16 liters
Last verified on 09-07-2026
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