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A container contains a mixture of milk and water in a ratio of 4:1. When 10 liters of the mixture are taken out and 10 liters of water are poured into the container and ratio becomes 2: 3. How many liters of milk were contained originally in the container?
  1. 16 litres
  2. 14 litres
  3. 12 litres
  4. None of these
Explanation

Initial ratio milk : water = 4 : 1  

Let initial milk = 4x  

Let initial water = x  

Total = 5x  

10 liters of mixture taken out.  

In the mixture, milk = 4/5 and water = 1/5  

Milk taken out = 10 × 4/5 = 8 liters  

Water taken out = 10 × 1/5 = 2 liters  

Remaining:  

Milk = 4x - 8  

Water = x - 2  

Now 10 liters of water is added.  

New Water = x - 2 + 10 = x + 8  

New Milk = 4x - 8  

New ratio milk : water = 2 : 3  

So,  

(4x - 8) / (x + 8) = 2 / 3  

Cross multiply:  

3(4x - 8) = 2(x + 8)  

12x - 24 = 2x + 16  

12x - 2x = 16 + 24  

10x = 40  

x = 4  

Original milk = 4x = 4 × 4 = 16 liters


Last verified on 09-07-2026

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