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The sum of three consecutive integers is 72. What is the smallest of three integers?
  1. 21
  2. 22
  3. 23
  4. 24
Explanation

Let the three consecutive integers be  x+1, and  x+2.

According to the problem, their sum is 72:

x+(x+1)+(x+2)=72

Combine like terms

3x+3=72

Subtract 3 from both sides: 

3x=69

Divide by 3: 

x=23

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