Two trains are moving in opposite directions at 60 km-hr and 90 km-hr. Their lengths are 1.10 km and 0.9 km respectively. What is the time taken by the slower train to cross the faster train in seconds?
- 48 seconds
- 45 seconds
- 36 seconds
- 49 seconds
Explanation
Speed of the two trains: 60 km/hr and 90 km/hr
If train cross each other, then effective speed = 60 + 90 = 150 km/hr
Length of first train = 1.10 km or 1100 m
Length of second train = 0.9 km or = 900 m
formula
Speed = Distance/Time
⇒ 150 × (5/18) = 2000/Time
⇒ 125/3 = 2000/Time
⇒ Time = 2000 × (3/125)
∴ Time = 48 seconds.
Relative speed = 60 + 90 = 150 km/hr. = 150 x 5/18 = 125/3 m/sec. Distance covered = 1.10 + 0.9 = 2 km = 2000 m. Required time = 2000 x 3/125 = 48 sec.
Related MCQs
- 80 km/h
- 72 km/h
- 100 km/h
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 180 km
- 160 km
- 140 km
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 45 km/h
- 48 km/h
- 50 km/h
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 120 km
- 100 km
- 140 km
- 80 km
اس سوال کو وضاحت کے ساتھ پڑھیں
- 30 km/h
- 40 km/h
- 50 km/h
- 60 km/h
اس سوال کو وضاحت کے ساتھ پڑھیں
