Ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old the younger one, find their present age _____?
- 12,28
- 14, 30
- 16, 32
- 18, 34
Explanation
Let younger person's age = xElder person's age = x + 16
6 years ago:
x + 16 - 6 = 3(x - 6)
x + 10 = 3x - 18
28 = 2x
x = 14
Younger = 14, Elder = 30
Last verified on 10-03-2026
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