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A father is 4 times older than his son. In 20 years he will be twice as old as his son. What age has father now?
  1. 48 years
  2. 44 years
  3. 36 years
  4. 40 years
  5. 32 years
Explanation

After 20 years, he will be twice as old as his son at that time. Find their present ages. Present age of the father is = 4 x = 4 × 10 = 40 4x=4\times10=40 4x=4×10=40 years.
Let the present age of the son be x, Father's present age= 4x After 20 years , Son's age = x+20 Father's age= 4x+20 Now given that after 20 years , father will be 2twice his son's age. so, 4x+20= 2(x+20) 4x+20=2x+40 4x-2x=40-20 2x= 20 x= 20/2 x= 10 years

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