The Mean Of Five Numbers Is 18. If One Number Is Excluded, Then Their Mean Is 16, The Excluded Number Is _____?

The mean of five numbers is 18. If one number is excluded, then their mean is 16, the excluded number is _____?

Explanation

Mean of $5$ numbers $= 18$
$\Rightarrow$ Sum of these $5$ numbers $= 18 \times 5 = 90$

Let number that has been excluded be $x$
New mean $= \frac{9 0 - x}{4} = 16$

Solving this, we get
$90 - x = 64$
$∴ x = 26$

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³√32768 = ____?

32
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36
None of these

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Simplify: (x²+x−20)/(x²−4)

(x+5)(x−4)/(x−2)(x+2)
x+5/x+2
x−4/x−2
x+5/x−2

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Explanation

(x²+x−20)/(x²−4)

Step 1: Factorize the numerator and denominator.

x²+ x - 20 = (x + 5) (x - 4)

x²- 4 = (x - 2) (x + 2)

Step 2: Write the simplified expression.

(x+5)(x−4)/(x−2)(x+2)

If 54 is subtracted from 3 times a number, the result is 36. What is the number?

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Find x, if log5 125 = x?

3
5
25
None of these

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If 3x + 1 = x, then x?

-1/2
-1/3
-1/4
None of these

The mean of five numbers is 18. If one number is excluded, then their mean is 16, the excluded number is _____?

Explanation

Mean of $5$ numbers $= 18$
$\Rightarrow$ Sum of these $5$ numbers $= 18 \times 5 = 90$

Let number that has been excluded be $x$
New mean $= \frac{9 0 - x}{4} = 16$

Solving this, we get
$90 - x = 64$
$∴ x = 26$

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The mean of five numbers is 18. If one number is excluded, then their mean is 16, the excluded number is _____?

Explanation

Mean of 5 numbers =18⇒ Sum of these 5 numbers =18×5=90Let number that has been excluded be xNew mean =490−x​=16Solving this, we get90−x=64∴x=26

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Mean of $5$ numbers $= 18$
$\Rightarrow$ Sum of these $5$ numbers $= 18 \times 5 = 90$

Let number that has been excluded be $x$
New mean $= \frac{9 0 - x}{4} = 16$

Solving this, we get
$90 - x = 64$
$∴ x = 26$