A Team Of 30 Men Is Supposed To Do A Work In 38 Days. After 25 Days, 5 More Men Were Employed And The Work Was Finished One Day Earlier. How Many Days Would It Have Been Delayed If 5 More Men Were Not Employed?

A team of 30 men is supposed to do a work in 38 days. After 25 days, 5 more men were employed and the work was finished one day earlier. How many days would it have been delayed if 5 more men were not employed?

4 day
2 day
1 day
None

Explanation

$35$ men completed the remaining job in $12 d a y s$ .
Now the same job has to be done by $30 m e n$ .
We know that, $M_{1} D_{1} = M_{2} D_{2}$
Required time $= \frac{3 5 \times 1 2}{3 0} = 14 d a y s$
Delayed time $= (14 - 13) = 1 d a y$

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A team of 30 men is supposed to do a work in 38 days. After 25 days, 5 more men were employed and the work was finished one day earlier. How many days would it have been delayed if 5 more men were not employed?

Explanation

$35$ men completed the remaining job in $12 d a y s$ .
Now the same job has to be done by $30 m e n$ .
We know that, $M_{1} D_{1} = M_{2} D_{2}$
Required time $= \frac{3 5 \times 1 2}{3 0} = 14 d a y s$
Delayed time $= (14 - 13) = 1 d a y$

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A team of 30 men is supposed to do a work in 38 days. After 25 days, 5 more men were employed and the work was finished one day earlier. How many days would it have been delayed if 5 more men were not employed?

Explanation

35 men completed the remaining job in 12 days.Now the same job has to be done by 30 men.We know that, M1​D1​=M2​D2​Required time =3035×12​=14 daysDelayed time =(14−13)=1 day

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$35$ men completed the remaining job in $12 d a y s$ .
Now the same job has to be done by $30 m e n$ .
We know that, $M_{1} D_{1} = M_{2} D_{2}$
Required time $= \frac{3 5 \times 1 2}{3 0} = 14 d a y s$
Delayed time $= (14 - 13) = 1 d a y$