If The Side Of A Square Is Increased By 25%, Then Its Area Gets Increased By

If the side of a square is increased by 25%, then its area gets increased by

56.25 %
50%
59 %
76.25 %

Explanation

Side of a square is increased by 25 %
Let the initial side be x
Initial area $= x^{2}$
New Side $= x + \frac{x}{4} = \frac{5 x}{4}$
New area $= \frac{2 5 x ^{2}}{1 6}$
increase in area $= \frac{9 x ^{2}}{1 6}$
$∴$ % increase $= \frac{9 0 0}{1 6} = 56.25$ %

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If the side of a square is increased by 25%, then its area gets increased by

Explanation

Side of a square is increased by 25 %
Let the initial side be x
Initial area $= x^{2}$
New Side $= x + \frac{x}{4} = \frac{5 x}{4}$
New area $= \frac{2 5 x ^{2}}{1 6}$
increase in area $= \frac{9 x ^{2}}{1 6}$
$∴$ % increase $= \frac{9 0 0}{1 6} = 56.25$ %

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If the side of a square is increased by 25%, then its area gets increased by

Explanation

Side of a square is increased by 25 % Let the initial side be xInitial area =x2New Side =x+4x​=45x​New area =1625x2​increase in area =169x2​∴ % increase =16900​=56.25 %

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Side of a square is increased by 25 %
Let the initial side be x
Initial area $= x^{2}$
New Side $= x + \frac{x}{4} = \frac{5 x}{4}$
New area $= \frac{2 5 x ^{2}}{1 6}$
increase in area $= \frac{9 x ^{2}}{1 6}$
$∴$ % increase $= \frac{9 0 0}{1 6} = 56.25$ %