LECTURER MATHEMATICS PAST PAPERS AND SYLLABUS
Lecturer Past Papers
چار آپشن میں سے کسی ایک پر کلک کرنے سے جواب سرخ ہو جائے گا۔
- (e^y + e^(-y)) / (e^y - e^(-y))
- (e^y + e^(-y)) / (e^y + e^(-y))
- (e^y - e^(-y)) / (e^y + e^(-y))
- None of these
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Explanation
The hyperbolic tangent function tanh(y) is defined as:
tanh(y) = (e^y - e^(-y)) / (e^y + e^(-y))
- Skilled
- Voracious
- Starving
- None of these
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Explanation
Ravenous means انتہائی بھوک یا لالچی
Voracious means ایک بہت بڑی بھوک یا کسی چیز کی خواہش کا ہونا
- 7
- 5
- 3
- None of these
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Explanation
Given n(n + 1)(n + 5):
1. n(n + 1) is always even (multiple of 2) since it's the product of two consecutive integers.
2. For divisibility by 3:
If n is a multiple of 3, the expression is divisible by 3.
If n = 3k + 1, then n + 5 = 3k + 6 is divisible by 3.
If n = 3k + 2, then n + 1 = 3k + 3 is divisible by 3.
Given these cases, n(n + 1)(n + 5) is divisible by 3.
- -a -2
- a - 2
- -2
- None of these
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Explanation
Given the operation a * b = a + b + 1:
Let's find the identity element 'e' such that a * e = a.
a * e = a + e + 1 = a
This implies e + 1 = 0, so e = -1.
Now, to find the inverse 'x' of 'a' such that a * x = e = -1:
a * x = a + x + 1 = -1
This implies a + x = -2.
x = -2 - a
x = -a - 2
- Bland
- Onslaught
- Nepotism
- None of these
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Explanation
Onslaught means a fierce or violent attack, which fits well with "by the enemy".
Onslaught means حملہ
- (0, - ∞)
- (-∞, ∞)
- R - (3)
- None of these
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Explanation
Given the function f(x) = 3x - 2
This is a linear function with a slope of 3. Since it's linear and defined for all real numbers x, its range is all real numbers.
As x varies from -∞ to ∞, f(x) also varies from -∞ to ∞.
- Truthfulness
- Carelessness
- Disparage
- None of these
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Explanation
Sedulity means کسی کے کام میں تندہی یا مستقل کوشش
Carelessness means توجہ یا کوشش کا فقدان
- Annihilate
- Integral
- Ameliorate
- None of these
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Explanation
"Annihilate" means to completely destroy, which fits the context of weapons and global threat.
Annihilate means فنا
- d²y/dx² + y = 4
- d²y/dx² + y = 0
- d²y/dx - y = 0
- None of these
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Explanation
Given y = acos(x) + bsin(x) + 4
First derivative: dy/dx = -asin(x) + bcos(x)
Second derivative: d²y/dx² = -acos(x) - bsin(x)
Notice that d²y/dx² = -(acos(x) + bsin(x))
Given y = acos(x) + bsin(x) + 4, we rearrange to find acos(x) + bsin(x) = y - 4
Substituting into the second derivative equation gives:
d²y/dx² = -(y - 4)
d²y/dx² = -y + 4
d²y/dx² + y = 4
The answer is d²y/dx² + y = 4.
- λ = 9
- λ = 6
- λ = 8
- None of these
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Explanation
Let's directly evaluate the system of equations:
1x + 3y = 1
3x + λy = 3
For infinitely many solutions, these equations must represent the same line. Multiplying the first equation by 3 gives:
3x + 9y = 3
Comparing this with the second equation 3x + λy = 3, we see that λ must equal 9 for the equations to be identical.