Explanation

Let average of 9 innings = x

Total runs in 9 innings = 9x

He scores 100 runs in 10th inning

New average = x + 8

Total runs in 10 innings = 10 _ (x + 8)

Now,

Total runs in 10 innings = Total runs in 9 innings + 100

So,

10 _ (x + 8) = 9x + 100

10x + 80 = 9x + 100

10x - 9x = 100 - 80

x = 20

Average after 9th inning = 20

Verified & Updated

Explanation

To find the average, we need to first convert each fraction to a decimal:

 5/6 = 0.83

 4/3 = 1.33

 3/4 = 0.75

Then, add the decimals and divide by the number of values:

 0.83 + 1.33 + 0.75 = 2.91

 2.91 ÷ 3 = 0.97

Now, convert the average back to a fraction:

 0.97 ≈ 35/36

Last verified on 01-07-2026

Explanation

Let old average after 9 innings = A  

Total runs after 9 innings = 9 × A

After 10th inning he scores 100  

New average = A + 8  

New total runs = 10 × (A + 8)

So: 9A + 100 = 10(A + 8)  

9A + 100 = 10A + 80  

100 - 80 = 10A - 9A  

20 = A

Old average = 20  

New average = 20 + 8 = 28

Last verified on 17-06-2026

Explanation

Arithmetic mean = (first number + second number) / 2

= ((x - y) + (x + y)) / 2

= (x - y + x + y) / 2

= (2x) / 2

= x

Last verified on 17-06-2026

Explanation

The average of the first n natural numbers is given by (n + 1) / 2.

For n = 97:

Average = (97 + 1) / 2

= 98 / 2

= 49

Last verified on 17-06-2026