Quadratic Equation 2x²-kx+5=0 To Have Equal Roots, What Should The Value Of K - Testpoint

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Quadratic equation 2x²-kx+5=0 to have equal roots, what should the value of K

±2√(10)
±4 √(10)
±10
±20

Explanation

Using formula:

$b^2-4ac=0$

Here:

$a = 2$
$b = - k$
$c = 5$

So:

$(- k)^^{2} - 4 (2) (5) = 0$ $k^^{2} - 40 = 0$ $k^^{2} = 40$

$\pm2\sqrt(10)$

$Last updated question NS on 10 MAY 2026$

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