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If roots of ax² + bx + c = 0 are reciprocals of roots of 2x² - 3x + 1 = 0 then a : b : c?
  1. 1:-2:3
  2. 2:-3:1
  3. 1:-3:2
  4. Nine of these
Explanation

For 2x² - 3x + 1 = 0:  

Sum = 3/2, Product = 1/2  

Let roots be α, β. Then new roots are 1/α, 1/β  

New sum = 1/α + 1/β = (α + β)/αβ = (3/2) / (1/2) = 3  

New product = 1/αβ = 1/(1/2) = 2  

New equation: x² - (sum)x + product = x² - 3x + 2 = 0  

So a:b:c = 1:-3:2


Last verified on 06-05-2026

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