If y = √(64 / (3x + 1)), find x when y = 4
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Explanation
y = √(64 / (3x + 1))
Square both sides: 16= 64 / 3x + 1
Now solve:
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y = √(64 / (3x + 1))
Square both sides: 16= 64 / 3x + 1
Now solve:
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