The sum of the ages of 3 children born at the intervals of 4 years each is 42 years. The age of the youngest child is ______ in years.
- 15
- 10
- 20
- None of these
Explanation
Let the ages be x, x+4, x+8
Sum = x + (x+4) + (x+8) = 42
3x + 12 = 42
3x = 30
x = 10
Age of youngest child = 10
Last verified on 18-03-2026
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