A sum of Rs. 4,200 is lent out in two parts such that for 8 years the interest on one part at 10% p.a. is equal to the interest on the other part at 7% p.a. for 5 years. What is the second part?
- Rs. 2,921
- Rs. 1,853
- Rs. 4,200
- Rs. 2,100
Explanation
Let the first part be x, lent at 10% for 8 years.
So, interest = (x × 10 × 8)/100 = 0.8x
Let the second part be (4200 − x), lent at 7% for 5 years.
So, interest = [(4200 − x) × 7 × 5]/100 = (35/100)(4200 − x) = 0.35(4200 − x)
Since both interests are equal:
0.8x = 0.35(4200 − x)
Solve:
0.8x = 1470 − 0.35x
0.8x + 0.35x = 1470
1.15x = 1470
x = 1278.26
So, second part = 4200 − 1278.26 = Rs. 2,921.74 ≈ Rs. 2,921
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