In an ideal transformer, if the primary voltage is doubled and the turns ratio remains the same, what happens to the secondary current?
- Doubles
- Halves
- Remains the same
- Becomes four times
Explanation
In an ideal transformer:
Vₚ / Vₛ = Nₚ / Nₛ (Voltage ratio = turns ratio)
And power is conserved:
Pₚ = Pₛ → Vₚ Iₚ = Vₛ Iₛ
If primary voltage (Vₚ) is doubled and turns ratio remains the same, then:
- Secondary voltage (Vₛ) also doubles (because turns ratio same).
- Power input doubles (assuming the same current on primary).
To keep power balanced, if secondary voltage doubles, then:
Iₛ = (Vₚ Iₚ) / Vₛ
Since Vₚ doubles and Vₛ doubles, secondary current remains the same (assuming primary current remains same).
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