In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
- 1/3
- 8/21
- 7/19
- None of these
Explanation
We are given:
-
Red balls = 8
-
Blue balls = 7
-
Green balls = 6
Total balls = 8 + 7 + 6 = 21
We are asked to find the probability that the ball is neither red nor green.
That means we want the probability that the ball is blue.
Number of favorable outcomes = Number of blue balls = 7
Probability = (Favorable outcomes) / (Total outcomes)
= 7/31
=1/3
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