A police officer walk from his house at 4 km per hour and reached his office 5 min late if his speed is 5 km per hour he will reach his office 10 min early. how far is his office from the house ?
- 5 km
- 5/12 km
- 2.5 km
- 10 km
Explanation
Let the distance between the police officer's house and office be D km.
Let the actual time required to reach the office on time be T hours.
Step 1: Forming Equations
Using the speed-time formula:
Speed
Case 1: Walking at 4 km/h
(since he is 5 minutes late, which is 5/60 hours)
Case 2: Walking at 5 km/h
(since he is 10 minutes early, which is 10/60 hours)
Step 2: Solving for Distance
From the first equation:
From the second equation:
Equating both expressions for T:
D
Multiply everything by 60 to clear the fractions:
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