Explanation

Explanation

Let's say the person's usual travel time to his office is x minutes.

Since he is walking at 5/6 of his usual speed, his new speed is 5/6 of his usual speed.

The time taken to cover the same distance at this new speed is 6/5 of his usual time (since speed and time are inversely proportional).

So, the new time taken = (6/5)x

Since he is 40 minutes late, the new time taken is 40 minutes more than his usual time:

(6/5)x = x + 40

Simplifying the equation:

(1/5)x = 40

x = 200 minutes

Converting x to hours and minutes:

x = 3 hours 20 minutes

Last verified on 13-11-2026

Explanation

Average speed ≠ average of speeds when distances are equal.  

Use: Average speed = Total distance / Total time

Total distance = 60 + 60 = 120 km

Time for 1st part = 60 km / 60 km/h = 1 hour  

Time for 2nd part = 60 km / 120 km/h = 0.5 hour  

Total time = 1 + 0.5 = 1.5 hours

Average speed = 120 / 1.5 = 80 km/h.

Last verified on 13-06-2026

Explanation

Assuming “10 past 5” means 5:10:

- Time elapsed since noon = 5 hours 10 minutes = 310 minutes.

- The hour hand moves 0.5° per minute.

Formula: 30° per hour = 0.5° per minute.

• 5 hours 10 minutes = 310 minutes

• 310 × 0.5° = 155°

  Last updated 08 Nov 2026 by NA

Explanation

First convert 10 minutes into hours:

• 1 hour = 60 minutes $1\text{ hour}=60\text{ minutes}$

• 10 minutes=10/60​=1/6​ hour

Distance = Speed × Time

d = vt

• Speed $v=60$ km/h

• Time $\frac{\mathrm{<span\; style="font-family:\; Overpass,\; sans-serif;\; font-size:\; 0.875rem;">t <span\; style="font-size:\; 0.875rem;">= </span><span\; class="vlist"\; style="font-size:\; 0.875rem;"><span\; class="sizing\; reset-size6\; size3\; mtight"><span\; class="mord\; mtight"><span\; class="mord\; mtight">1</span></span></span></span><span\; class="vlist-s"\; style="font-size:\; 0.875rem;">/6\; h </span></span>}}{}$

d=60×1/6​=10 km

Last updated 08 Nov 2026 by NA